Chapter 5:
ch 5, #5)
a) i = 0.388 A counter clockwise
b) i = 2.087 A clockwise
Notice: these directions are different than the answers in the text
5.12
a) V=40V; i=(40/20)=2A; R=(80V/2A)=40 ohm
b) i = (8/2.2) = 3.636A; V1=R1*i=4.7 * 3.636 = 17.1V; V2=24.7V; E=8+17.1+24.7 = 49.8V
c) use P=(I**2)R, find R= 21 ohm; V1 = RI = 2V; V2 = 1V; V3 = 21V; E = V1+V2+V3 = 24V
d) I= 2A; R1 = 2 ohm; R2 = 13 ohm; E = Rt*I = 32V
5.15 Vab =
a) 66.7V
b) -8V (polarity is drawn 'backwards')
c) 20V
d) 0.18V (combine the 1.5, .6 and .9 R's)
5.17
a) V2 = 3 * R2 / Rt = 12V
b) V3 = 40 - 12 - 4 = 24V
c) R3 = 2*R2 = 60 ohm
d) i = V/R = 4/10 = 0.4A
e) R3 = V3/I3 = 24/0.4 = 60 ohm
Chapter 6:
6.3
a) Rt= 6 ohm
b) Rt= 1 kohm
c) Rt= 2.076 kohm
d) Rt= 1.33 ohm
e) Rt= 0.689 ohm
6.5
a) R = 18 ohm
b) R = 24 ohm