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Laboratory 3.2 (cont)

  • * bits 0-3 only, ā€œNā€ means N bit (bit 3) is 1

  • $F6 % 1111 0110 -10

  • +$57 % 0101 0111 $57 = 5*16 + 7 = 87

  • $14D % 1 0100 1101 $4D = 4*16 + 13 = 77

  • ^ (carry out of bit 7occurs)

  • -10 + 87 = 77 < 127 so no overflow occurs


    Notes: