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Laboratory 3.2 (cont)

  • * bits 0-3 only, ā€œNā€ means N bit (bit 3) is 1

  • $3F % 0011 1111 3*16+15 = 48+15 = 63

  • +$70** % 0111 0000 7*16 = 112

  • $AF % 1010 1111 175 > 127

  • **NOT(1001 0000) + 1 =% 0110 1111+1 = % 0111 0000 = $70

  • $AF % 1010 1111 ($50+ 1 = $51 = 81 and 63-144 =-81)

  • Answer is correct even though overflow occurs.


    Notes: